Posted by Hester on Monday, December 5, 2011 at 4:22pm.
m1= mass of the bullet
m2= mass of the block
Vf=sqrt(2gh)
v1= initial velocity of bullet
v2= initial velocity of the block = 0
so
first is conservation of momentum
m1v1+m2v2=(m1+v2)Vf
solve for v1 (note m2v2=0)
v1=((m1+m2)/m2)/Vf
to find Vf look at conservation of energy
KE+PE=KE'+PE'
.5(m1+m2)Vf^2+0=0+(m1+m2)gh
Solve for Vf and you get Vf=Sqrt(2gh)
now v1=((m1+m2)/m2)/(sqrt(2gh)) and solve
v1= 15.715 m/s
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