Posted by **Javan** on Monday, December 5, 2011 at 3:35pm.

For a damped simple harmonic oscillator, the block has a mass of 2.4 kg and the spring constant is 14 N/m. The damping force is given by -b(dx/dt), where b = 260 g/s. The block is pulled down 11.0 cm and released. (a) Calculate the time required for the amplitude of the resulting oscillations to fall to 1/4 of its initial value. (b) How many oscillations are made by the block in this time?

## Answer this Question

## Related Questions

- physics - A mass of 0.394 kg is attached to a spring with a spring constant of ...
- physics - In the figure below, a damped simple harmonic oscillator has mass m = ...
- Harmonic Oscillation - The velocity of a certain simple harmonic oscillator is ...
- physics help - Damped Oscillations 1. (a) For each of following graphs, ...
- damped oscillator - How do I show mathematically that Q is equal to the ...
- physics - A body with mass 0.30 kg hangs by a spring with force constant 50.0 N/...
- gfd - A 10.6 kg object oscillates at the end of a vertical spring that has a ...
- physics - A simple harmonic oscillator consists of a 1.1 kg block attached to a ...
- PHYsics !! - a) What do you understand by Simple Harmonic Motion? b) A simple ...
- Physics - A simple harmonic oscillator consists of a block of mass 1.70 kg ...

More Related Questions