Posted by **leav** on Monday, December 5, 2011 at 3:14pm.

A 1680- kg rocket is launched with a velocity v0 = 55 m/s against a strong wind. The wind exerts a constant horizontal force Fwind = 15600 N on the rocket. At what launch angle will the rocket achieve its maximum range?

- physics -
**bobpursley**, Monday, December 5, 2011 at 5:30pm
horizontalacceleration= F/m

distance horzontal due to force= 1/2 F/m*t^2

distance horizontal= 55*cosTheta*t+1/2 F/Mass*t^2

Now, time in air:

hf=hi=0=55sinTheta*t-1/2 g t^2

or t= 110sinTheta/g

put that time in distance horizontal, then take the derivative of distance/dt and set to zero, solve for theta.

Interesting question.

- physics -
**leav**, Friday, December 9, 2011 at 9:38pm
I DONT UNDERSTAND.

WHAT IS: distance horzontal due to force= 1/2 F/m*t^2

and what do you mean by:

put that time in distance horizontal, then take the derivative of distance/dt and set to zero

if you can explain in more details it will help

thanks alot

## Answer This Question

## Related Questions

- Physics - A model rocket is launched from rest with an upward acceleration of 6....
- physics - A model rocket is launched from rest with an upward acceleration of 5....
- Grade 11 physics - After reaching its highest point the blue ninja rocket's ...
- Math - A rocket is launched into the sky on a windy day. The rocket has a ...
- Physics - A 360 g model rocket is on a cart that is rolling to the right at a ...
- Physics - A rocket blasts off vertically from rest on the launch pad with an ...
- physic - Q: a model rocket was launched and measurements of its height and ...
- Physics - You launch a model rocket up into the sky. Right after launch the ...
- physics - You launch a model rocket up into the sky. Right after launch the ...
- physics - You launch a model rocket up into the sky. Right after launch the ...

More Related Questions