Posted by Anonymous on Monday, December 5, 2011 at 2:59pm.
moles HCl = M x L = ?
moles NaOH = M x L = ?
Write the equation. Which is there in excess. Subtract moles of the greater from moles of the lesser. The pH of the solution will be determined by the excess HCl or excess NaOH (depending upon the numbers). Then pH = -log(H^+) OR pOH = -log(OH^-)
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