chemistry
posted by Anonymous on .
An atom of ^241Am95 undergos alpha decay and produces an alpha particle. The resulting element is:
^239Am91
^235Np93
^241Pu94
^241Cm96
^243Am95

To use your symbolism, although it isn't the best in the world I know what you mean, it works this way.
^241Am95 ==> ^4He2 + ^yXz
If you will ALWAYS do this, you can figures these out very simply. Here is what you do. The exponents must add up on both sides. The subscripts must add up on both sides. Easy, isn't it.
So 241 = 4 + y for the superscripts
and 91 = 2 + z for the subscripts.
Just calculate y and z and you have it
Then X is the element with atomic number = z.
The right answer is not listed if you posted the question correctly.