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posted by Anonymous on Monday, December 5, 2011 at 2:45pm.
A particular solution has a [H3O+] 2.44 x 10^-4. Therefore, the [OH-]= 4.10 x 10^3 4.10 x 10^-11 2.44 x 10^-4 1.71 x 10^-8 9.09 x 10^-16
(H^+)(OH^-) = Kw = 1E-14
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