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Posted by Anonymous on Monday, December 5, 2011 at 2:45pm.

A particular solution has a [H3O+] 2.44 x 10^-4. Therefore, the [OH-]= 4.10 x 10^3 4.10 x 10^-11 2.44 x 10^-4 1.71 x 10^-8 9.09 x 10^-16

(H^+)(OH^-) = Kw = 1E-14

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