You have 26.44 mL of 1.83 M HCl in a beaker. You dilute this acid with 40.08 mL of water. When you analyze the solution you find that the number of moles of HCl in the new solution is
old moles = old M x old L. Do you change th moles HCl by adding 40.08 mL water?
To find the number of moles of HCl in the new solution, we can use the formula:
moles = concentration x volume
First, let's calculate the number of moles of HCl in the original solution:
moles of HCl = concentration x volume
= 1.83 M x 26.44 mL
To perform this calculation, we need to convert the volume from milliliters (mL) to liters (L):
volume = 26.44 mL ÷ 1000
= 0.02644 L
Now we can calculate the number of moles of HCl:
moles of HCl = 1.83 M x 0.02644 L
Next, let's determine the final volume of the solution after diluting it:
final volume = volume of HCl + volume of water
= 26.44 mL + 40.08 mL
Again, we need to convert the volume from milliliters (mL) to liters (L):
final volume = (26.44 mL + 40.08 mL) ÷ 1000
= 66.52 mL ÷ 1000
= 0.06652 L
Finally, we can calculate the new concentration of the diluted solution:
new concentration = moles of HCl / final volume
= (1.83 M x 0.02644 L) / 0.06652 L
Simplifying the equation:
new concentration = 0.048 L
Hence, the number of moles of HCl in the new solution is 0.048 moles.