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September 22, 2014

September 22, 2014

Posted by **help fast please** on Monday, December 5, 2011 at 11:48am.

- Calculus -
**Steve**, Monday, December 5, 2011 at 12:07pmif the distance is s,

s^2 = x^2 + y^2

2s ds/dt = 2x dx/dt + 2y * 2x dx/dt

2s ds/dt = (2x^2 + 2x + 2) dx/dt

s ds/dt = (x^2+x+1)(2)

ds/dt = 2(x^2+x+1)/sqrt(x^4 + 3x^2 + 1)

If you know x, plug it in

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