A sample of gas has an initial volume of 2.80 L at 755 torr. If the volume of the gas is increased to 3.70 L, what will the pressure be?

P1V1 = P2V2

To find the final pressure, we can use the combined gas law, which states that the ratio between the initial pressure and volume is equal to the ratio between the final pressure and volume. The formula is as follows:

(P1 * V1) / T1 = (P2 * V2) / T2

In this case, we are given the initial pressure (P1) as 755 torr and the initial volume (V1) as 2.80 L. We are also given the final volume (V2) as 3.70 L. We need to find the final pressure (P2).

First, we can rearrange the formula to solve for P2:

P2 = (P1 * V1 * T2) / (V2 * T1)

Now, we need to assume that the temperature is constant for this problem since it is not given. Therefore, T1 and T2 will be the same.

Substituting in the given values, we have:

P2 = (755 torr * 2.80 L) / (3.70 L * T)

Since the temperature cancels out, we can disregard it for this problem.

P2 = (755 torr * 2.80 L) / (3.70 L)

P2 = 575.95 torr

Therefore, the final pressure of the gas when the volume is increased to 3.70 L will be approximately 575.95 torr.