Post a New Question


posted by on .

When 71.43 mL of 0.855 M HNO3 is diluted with 20.57 mL of water, the molarity of the nitric acid becomes

  • chemistry - ,

    The dilution is
    c1v2 = c2v2 but I prefer to reason it saying M has been diluted by how much?
    0.855M x (71.43 mL/(71.43+20.57) = ?
    By the way, this assumes that the volumes are additive which is not always the case.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question