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October 1, 2014

October 1, 2014

Posted by **CC** on Monday, December 5, 2011 at 11:22am.

- Algebra 102 -
**Steve**, Monday, December 5, 2011 at 11:57amset everything as powers of 3:

(3^2)^x = 3^(-3)

3^2x = 3^(-3)

since powers equal (or, take log base 3 of both sides),

2x = -3

x = -3/2

check:

9^(-3/2) = 1/9^(3/2) = 1/3^3

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