Posted by Kelly on Monday, December 5, 2011 at 10:37am.
A rectangle garden is 30 ft by 40 ft. Part of the garden is removed in order to install a walkway of uniform width around it. The area of the new garden is onehalf the area of the old garden. How wide is the walkway?

math word problem  Steve, Monday, December 5, 2011 at 11:55am
Let the walkway have width w
The new dimensions of the garden are
(302w) x (402w)
That's half of the original area, 30x40
(302w)(402w) = 1/2 * 30*40
1200  140w + 4w^2 = 600
4w^2  140w + 600 = 0
w^2  35w + 150 = 0
(w5)(w30) = 0
w=30 doesn't make much sense. No garden left
w=5 means that the new garden is
20x30 = 1/2 of 30x40 
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