How many grams of N2 are needed to react with 125g of H2?
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To determine the number of grams of N2 needed to react with 125g of H2, we need to use the balanced chemical equation for the reaction between N2 and H2.
The balanced equation for the reaction is:
N2 + 3H2 → 2NH3
From the equation, we can see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.
To find the number of moles of H2 in 125g of H2, we divide the given mass by the molar mass of H2:
Molar mass of H2 = 2g/mol
Moles of H2 = Mass of H2 / Molar mass of H2
= 125g / 2g/mol
= 62.5 mol
From the balanced equation, we can see that the ratio of N2 to H2 is 1:3. Therefore, 1 mole of N2 reacts with 3 moles of H2.
Moles of N2 = Moles of H2 x (1 mol N2 / 3 mol H2)
= 62.5 mol x (1 mol N2 / 3 mol H2)
= 20.83 mol N2
Finally, we can find the mass of N2 by multiplying the moles of N2 by its molar mass:
Molar mass of N2 = 28g/mol
Mass of N2 = Moles of N2 x Molar mass of N2
= 20.83 mol x 28g/mol
= 582.44g
Therefore, you would need approximately 582.44 grams of N2 to react with 125 grams of H2.