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November 27, 2014

November 27, 2014

Posted by **Julia** on Monday, December 5, 2011 at 9:57am.

would it be sigma sign in middle (3) on top of sign, n=0 on bottom of signma notation and to the right it would be (4+2n)

so it would look like--

(3)

(sigma in middle) (4+2n)

n=0

- Algebra II -
**Reiny**, Monday, December 5, 2011 at 10:20amYours will work

If I recall, the index in sigma notation usually starts with 1, so you could have

4

∑ (2+2n)

n=1

There is no unique way to state the result.

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