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September 2, 2014

September 2, 2014

Posted by **hannah** on Monday, December 5, 2011 at 6:21am.

(6380 km ). Use the inverse-square law to show that in space-shuttle territory, 200 km above the earths surface the force of gravity on a shuttle is about 94% of that at the earths surface.

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**drwls**, Monday, December 5, 2011 at 7:06amLet the acceleration of gravity at 200 km altitude be g' and the value at sea level be g. Then

g'/g = (6380/6580)^2 = 0.94013

The rounds off to 94%, to the nearest 1%.

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