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July 26, 2014

July 26, 2014

Posted by **fareha** on Sunday, December 4, 2011 at 10:26pm.

a. Find an expression for y’

b. Write an equation for line l

- calculus -
**Steve**, Monday, December 5, 2011 at 11:33amdifferentiate implicitly:

4x^3 - 10xy^2 - 10x^2yy' + 16y^3y' = 0

y'(16y^3 - 10x^2y) = 10xy^2 - 4x^3

y' = x(5y^2 - 2x^2) / y(8y^2 - 5x^2)

-----------------

y'(2) = 2(5-8) / (8-20) = -6/-12 = 1/2

Line l is (y-1)/(x-2) = 1/2

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