a man applies a force of 220 N horizontally to the right against a 50 kg crate. the force of friction between the crate and the floor is 200 N. if the crate is pushed 2.0 m, the work done is....
What formula would be applicable?
ur wrong it's 400 lol
troy bolting away from this mess bYE
Get Wrekt m8
To find the work done in this scenario, you can use the formula:
Work = Force × Distance × cos(θ)
Where:
- Work is the amount of energy transferred when a force is applied to an object and it moves a certain distance.
- Force is the magnitude of the applied force.
- Distance is the distance the object moves in the direction of the applied force.
- θ (theta) is the angle between the force vector and the direction of motion.
In this case, the force applied by the man is 220 N horizontally to the right, and the crate is pushed 2.0 m. The angle θ is not given, but since the force and displacement are both horizontal, we can assume θ = 0°, so the cos(0°) = 1.
Substituting the values into the formula:
Work = 220 N × 2.0 m × cos(0°)
Work = 440 N·m
Therefore, the work done on the crate is 440 joules (J).
Applied force x distance moved = Work done
Work done = 220 * 2.0 = 440 J
The mass and friction force do not matter when computing work, but they do influence the acceleration rate.