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December 22, 2014

December 22, 2014

Posted by **Alex** on Sunday, December 4, 2011 at 7:25pm.

[10-(1/10)^2]+[10-(2/10)^2]+[10-(3/10)^2]+[10-(4/10)^2]

- precalc -
**Reiny**, Sunday, December 4, 2011 at 8:55pmJust look at the pattern. The only thing that changes is the denominator.

would it not be ..

4

∑ (10 - i/10)^2

i=1

?

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