Posted by deandra on Sunday, December 4, 2011 at 6:45pm.
Values of population not indicated. We do not know what is contained in Table 3. If Table 3 is the one I describe below, the answer is yes, if the distribution is approximately normal.
Z = (score-mean)/SD or SEm for distribution of means.
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.
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