Find the total area bounded by the curves y = x^3 and y = x^5 .

The curves intersect at x=0 and x=1, hence they are the limits of integration.

Using vertical slices of width dx, we have:
A=∫(x^3-x^5)dx from 0 to 1
=[x^4/4-x^6/6] from 0 to 1
=1/12