Homework Help: geometry

Posted by Cj on Sunday, December 4, 2011 at 1:44pm.

Gerrad is a painter. he is using a canvas that is in the shape of a regular hexagon. The perimeter of the canvas is 78 in. The perpendicular distance from a side to the center is 11 in. to the nearest inch. Based on these measurements, what is area of the canvas

geometry - MathMate, Sunday, December 4, 2011 at 1:54pm
Divide the canvas into 6 isosceles triangles.
Base of triangle = 78/6=13"
Height of triangle = 11"
Area of each triangle = 11*13/2
Total area of canvas=11*13/2*6=432 sq.in.
geometry - correction - MathMate, Sunday, December 4, 2011 at 1:58pm
Divide the canvas into 6 isosceles triangles.
Base of triangle = 78/6=13"
Height of triangle = 11"
Area of each triangle = 11*13/2
Total area of canvas=11*13/2*6=429 sq.in.

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