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Math

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I need help with this question,

it says to find the instantaneous rate at distance t = 6s with the given graph

First of all, it is a linear line,

do i need to find the equation of the graph?

After finding the equation, i plug in 5.99 and 6.01? and solve ?

  • Math - ,

    If it is truly linear, the rate (slope of the line) is the same as the instantaneous rate at all times.
    Try 5.99 and 6.01, it should give the same answer as 5 and 7.

  • Math - ,

    i got 0.25 answer, I wish I could show you the graph... T.T

  • Math - ,

    I do not know the domain of the graph (i.e. the max min values of t), but if you try different intervals, and if they always give the same answer of 0.25, you should be OK.

    If you can scan the graph and post it at one of the image sites and post the link, then we can all see it. However, I believe it is not necessary if the graph is truly linear.

  • Math - ,

    Here is the link

    imgur dot com/3V1AX


    The question asks: A distance versus time graph is shown below. What is the instantaneous rate of change in the distance at t=6s


    sorry, it won't rotate, you can save the pic and rotate >.<

  • Math - ,

    I can't post exact link due to errors :S

  • Math - ,

    Yes, it looks like the graph between (4,3) and (8,4) is a straight line, so if you apply the formula for slope:
    m=(4-3)/(8-4)=1/4 as you had it.

    Since t=6 is within the above interval of [4,8], the calculated value of slope (m=1/4) applies.

  • Math - ,

    So I am right? =D

  • Math - ,

    Btw, may I post another question here with image, I just want you to verify if I am correct :|

  • Math - ,

    Yes, your answer is correct.
    Feel free to post another question with image, but with a new thread. Posts tagged onto old threads tend to get lost.

  • Math - ,

    Ok, thanks~

  • Math - ,

    You're welcome!

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