algebra
posted by Anonymous on .
three times a first number decreased by a second number is 25. the first number increased by four times the second number is 22. find the numbers

3xy=25
x+4y=22
3xy=25
3x12y=66
13y=91
y=7
x+4(7)=22
x=6 
first number  x
second number y
translation:
" three times a first number decreased by a second number is 25" > 3x  y = 25
" the first number increased by four times the second number is 22" > x + 4y = 22
form 2nd equation: x = 4y  22
sub into 1st equation:
3(4y22)  y = 25
12y  66  y = 25
13y = 91
y = 7
then x = 2822 = 6
First number is 6, then second is 7
check:
3(6)  (7) = 25
6 + 4(7) = 22 , looks good 
Three times a number, decreased by 28.