Posted by mar13 on Sunday, December 4, 2011 at 7:58am.
At equilbrium, the melted ice (mass m) and the water it changes into will gain as much heat as the original coffee (mass M) loses.
0.140g*(89 - T)*4186
= 0.011*[333,000 + T*4186]
52,160 -586 T = 3663 + 46 T
632 T = 48,497
T = 77 C
Solve for final temperature T
Heat releasing from coffee (water in this case) is equal to the heat gain for ice melting to water at 0 deg plus water to raise for the final temp.
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