Posted by Tomomi on Sunday, December 4, 2011 at 5:27am.
A 650 N student stands on a scale in an elevator. As the elevator starts to move, the scale reads 780 N.
a. Find tha acceleration.
b. Is the elevator going up or down?

Physics  drwls, Sunday, December 4, 2011 at 5:46am
a. Since Fnet = m a, a = Fnet/m
Now we need values for the net force and the mass.
Fnet = 780  650 = 130 kg m/s^2
is the net force acting on the student.
The mass m is weight/g = 650/g
= 66.3 kg
a = 130/66.3 = 1.96 m/s^2
b. The student could be accelerating while going up, or decelerating while going down.
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