Posted by **Tomomi** on Sunday, December 4, 2011 at 5:27am.

A 650 N student stands on a scale in an elevator. As the elevator starts to move, the scale reads 780 N.

a. Find tha acceleration.

b. Is the elevator going up or down?

- Physics -
**drwls**, Sunday, December 4, 2011 at 5:46am
a. Since Fnet = m a, a = Fnet/m

Now we need values for the net force and the mass.

Fnet = 780 - 650 = 130 kg m/s^2

is the net force acting on the student.

The mass m is weight/g = 650/g

= 66.3 kg

a = 130/66.3 = 1.96 m/s^2

b. The student could be accelerating while going up, or decelerating while going down.

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