Posted by Tomomi on Sunday, December 4, 2011 at 5:27am.
a. Since Fnet = m a, a = Fnet/m
Now we need values for the net force and the mass.
Fnet = 780 - 650 = 130 kg m/s^2
is the net force acting on the student.
The mass m is weight/g = 650/g
= 66.3 kg
a = 130/66.3 = 1.96 m/s^2
b. The student could be accelerating while going up, or decelerating while going down.
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