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A 650 N student stands on a scale in an elevator. As the elevator starts to move, the scale reads 780 N.
a. Find tha acceleration.
b. Is the elevator going up or down?

  • Physics -

    a. Since Fnet = m a, a = Fnet/m
    Now we need values for the net force and the mass.

    Fnet = 780 - 650 = 130 kg m/s^2
    is the net force acting on the student.

    The mass m is weight/g = 650/g
    = 66.3 kg

    a = 130/66.3 = 1.96 m/s^2

    b. The student could be accelerating while going up, or decelerating while going down.

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