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March 25, 2017

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A bowling ball of mass M and radius R is thrown along a level surface so that initially ( t= 0) it slides with a linear speed but does not rotate, see the figure. As it slides, it begins to spin, and eventually rolls without slipping.

How far has the ball moved down the lane when it starts rolling without slipping?

What are its final linear speed?

What are its final rotational speed?

Thanks:]

  • Physics - ,

    You need to specify kinetic friction coefficient and the initial velocity.

  • Physics - ,

    it says to answer it in terms of those coefficients

  • Physics - ,

    like, it's asking for formulas...

  • Physics - ,

    Initial w, angular velocity, is zero.
    now while sliding
    torque = I alpha
    mu m g r = (2/5) m r^2 alpha
    alpha = (5/2) mu g / r
    and
    F = m a
    mu m g = m a
    a = mu g
    w = alpha t
    v = Vi - a t
    when does w r equal v (no slip)
    r alpha t = v = Vi - a t
    (5/2) mu g t = Vi - mu g t
    (7/2)mu g t = Vi
    so
    t = (2/7)Vi/(mu g)
    that is the time sliding
    work back up to get distance and final v

    Check that with energy argument:
    frictional work done = mu m g d

    Initial Ke - frictional work = Final Ke
    (1/2) m Vi^2 - mu m g d = (1/2) m v^2 +(1/2) (2/5) m r^2 (v^2/r^2)

    Vi^2 - 2 mu g d = (7/5)v^2

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