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March 31, 2015

March 31, 2015

Posted by **Fareha** on Saturday, December 3, 2011 at 10:29pm.

a. Find an expression for y’

b. Write an equation for line l

- calculus -
**drwls**, Saturday, December 3, 2011 at 11:06pma. Differentiate implicitly.

4x^3 -10x*y^2 -5x^2*2y*dy/dx +16y^3*dy/dx = 0

4x^3 -10x*y^2 -10 x^2*y*dy/dx +16y^3*dy/dx = 0

Plug in x = 2 and y = 1 to get dy/dx.

4 -20 -40 dy/dx +16 dy/dx = 0

-24 dy/dx = 16

dy/dx = -2/3

b. (y - 1)/(x-2) = -2/3

Check my work.

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