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September 1, 2014

September 1, 2014

Posted by **Anil** on Saturday, December 3, 2011 at 6:12pm.

- algebra -
**MathMate**, Saturday, December 3, 2011 at 8:26pme^x / 3 = 5^x

take logs to base e:

x-log(3) = xlog(5)

group terms to get

x(log(5)-1)=-log(3)

x = -log(3)/(log(5)-1)

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