Posted by **madad** on Saturday, December 3, 2011 at 4:27pm.

A photo width of 8cm, length of 14cm .if the perameter of photo is increased by 5o % , which dimension is for new perimeter.

options are:

16cm by 28cm

12cm by 21cm

4cm by7cm

8cm by28 cm

i chose the first option cuz it increased 50.but i ma not sure if i am right.

- Math -
**Ms. Sue**, Saturday, December 3, 2011 at 4:32pm
Present perimeter: 16 + 28 = 44

44 * 1.5 = 66 = new perimeter

The perimeter you chose is 32 + 56 = 88

Check out the other options. Which produces a perimeter of 66 cm?

- Math -
**hiba**, Saturday, December 3, 2011 at 4:44pm
8cm by 28 cm ?

I am confused . Geometery is not my thing .

- Math -
**Ms. Sue**, Saturday, December 3, 2011 at 5:01pm
P = 2L + 2W

Present perimeter:

P = 2(8) + 2(14)

P = 16 + 28

P = 44

- Math -
**hiba**, Saturday, December 3, 2011 at 5:22pm
it make sense so , just apply the Perameter formula and put the valuse so answers is 44 then 44*1.5 = 66.

But How i have deal with increased 50% deminsion thing .

please can you simplfy this .

- Math -
**Ms. Sue**, Saturday, December 3, 2011 at 5:33pm
Use trial and error.

Using your choices, figure out the perimeter for each set of dimensions.

P = 2L + 2W

Which produces a perimeter of 66?

- Math -
**hiba**, Saturday, December 3, 2011 at 5:45pm
12cm by 21cm = 2*33= 66

??

- Math -
**Ms. Sue**, Saturday, December 3, 2011 at 5:47pm
Let's check it out.

P = 2(21) + 2 (12)

P = 42 + 24

P = 66

Right!

- Math -
**hiba**, Saturday, December 3, 2011 at 6:11pm
Thanks.

- Math -
**Ms. Sue**, Saturday, December 3, 2011 at 6:22pm
You're welcome.

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