Posted by **ddd** on Friday, December 2, 2011 at 9:11pm.

solve inequalite place in interval notation

4-x/x-6<=0

- algebra -
**MathMate**, Friday, December 2, 2011 at 9:46pm
f(x)=(4-x)/(x-6)

First make a sketch of the equation (equality).

As x -> ± &infin, f(x) approaches -1.

There is also a vertical asymptote at x=6, approaching +∞ at 6- and -∞ at 6+. Therefore the function is discontinuous at that point.

The one zero is at x=4, where the function crosses from negative to positive.

If you have the sketch in front of you, it would be easy to find the places where the function is negative (≤0):

from -∞ to 4, and from 6+ to ∞.

If you need help putting that in interval notation, please post.

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