Posted by melissa on Friday, December 2, 2011 at 2:44pm.
a)Let HA = the weak acid, proanoic acid.
..............HA ==> H^+ + A^-
initial......0.300....0......0
change.........-x......x......x
equil........0.300-x...x.......x
Ka = (H^+)(A^-)/(HA)
Substitute from the ICE chart and solve for x, then convert to pH.
b)
This is a salt and the pH will be determined by the hydrolysis of the salt.
A^- + HOH ==> HA + OH^-
Set up an ICE chart similar to the one in (a) and solve for OH^-, then convert to pH.
(c) Pure water ionizes as
HOH => H^+ + OH^-
Set up an ICE chart and use
Kw = (H^+)(OH^-), solve for H^+ and convert to pH.
(d)
This is a buffered solution. Use the Henderson-Hasselbalch equation.
Post your work if you get stuck.
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