Posted by melissa on Friday, December 2, 2011 at 2:44pm.
Calculate the pH of each of the following solutions.
(a) 0.300 M propanoic acid (HC3H5O2, Ka = 1.3 10-5)
(b) 0.300 M sodium propanoate (NaC3H5O2)
(c) pure H2O
(d) 0.300 M HC3H5O2 and 0.300 M NaC3H5O2
- chemistry - DrBob222, Friday, December 2, 2011 at 6:27pm
a)Let HA = the weak acid, proanoic acid.
..............HA ==> H^+ + A^-
Ka = (H^+)(A^-)/(HA)
Substitute from the ICE chart and solve for x, then convert to pH.
This is a salt and the pH will be determined by the hydrolysis of the salt.
A^- + HOH ==> HA + OH^-
Set up an ICE chart similar to the one in (a) and solve for OH^-, then convert to pH.
(c) Pure water ionizes as
HOH => H^+ + OH^-
Set up an ICE chart and use
Kw = (H^+)(OH^-), solve for H^+ and convert to pH.
This is a buffered solution. Use the Henderson-Hasselbalch equation.
Post your work if you get stuck.
Answer This Question
More Related Questions
- Chemistry - Calculate the pH after 0.011 mol NaOH is added to 1.00 L of each of ...
- Chemistry - Need help with AP chemistry, specifically Acids and Bases The acid ...
- Chemistry - What is the pH of a solution containing 0.10 M propanoic acid (...
- chemistry - calculate the pH after 0.02 mol NaOH is added to 1.00 L of .1 M ...
- ap chemistry - For propanoic acid (HC3H5O2, Ka = 1.3 10-5), determine the ...
- Chemistry - What is the pH of a 1.00 L solution of the following buffer 0.500 M ...
- Mahts - The perimeter of a field is 300m and its length is 100m. What is its ...
- Chem - For a solution that is 0.280 M HC3H5O2 (propanoic acid Ka=1.3*10^-5) and ...
- Chemistry - Suppose 300.0 mL of 0.50 M HCl and 300.0 mL of 0.50 M NaOH, both ...
- Math (trigonometry) - From a boat on the water, the angle of elevation of the ...