Posted by LaurenB on Friday, December 2, 2011 at 2:21pm.
c_hot = (4.184J/g*K)(18mL)(1g/mL)
c_cold = (4.184J/g*K)(19mL)(1g/mL)
Use:
0 = c_hot(T_f - T_initial,hot)+ c_cold(T_f - T_initial,cold)
Solve for T_f and remember to convert temperature back to C from Kelvin and vice versa.
Best of luck,
ChemVantage Loather
Just a quick note to say that changing celsius to kelvin and back again is not necessary. Since it is a difference of temperatures only, and since 1 degree C = 1 degree K, you may subtract with C or K and come up with the same value.
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