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January 27, 2015

January 27, 2015

Posted by **Anonymous** on Friday, December 2, 2011 at 1:51pm.

- math -
**Steve**, Friday, December 2, 2011 at 2:35pmConsider the height h of the pole above their eyeballs.

Let Kate be x meters from the pole

h/x = tan 25°

h/(100-x) = tan 60°

x tan 25° = (100-x)tan 60°

.4663x = 173.205 - 1.7321x

2.1984x = 173.205

x = 78.79

So, Kate is 78.79m from the pole and

John is 21.21m from the pole.

h = 78.79 tan 25° = 36.74

so, the pole is 36.74 + 1.5 = 38.24m high (assuming their eyeballs are on top of their heads...)

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