Sunday

March 29, 2015

March 29, 2015

Posted by **Anonymous** on Friday, December 2, 2011 at 1:51pm.

- math -
**Steve**, Friday, December 2, 2011 at 2:35pmConsider the height h of the pole above their eyeballs.

Let Kate be x meters from the pole

h/x = tan 25°

h/(100-x) = tan 60°

x tan 25° = (100-x)tan 60°

.4663x = 173.205 - 1.7321x

2.1984x = 173.205

x = 78.79

So, Kate is 78.79m from the pole and

John is 21.21m from the pole.

h = 78.79 tan 25° = 36.74

so, the pole is 36.74 + 1.5 = 38.24m high (assuming their eyeballs are on top of their heads...)

**Answer this Question**

**Related Questions**

Math - A 15 m flagpole stands on level ground. from point P, due west of the ...

maths - John wishes to determine the height of a flagpole. He takes a sighting ...

MATH TRIG - FROM A DISTANCE OF 80 M. THE ANGLE OF ELEVATION OF THE TOP OF A ...

Algebra - In 1915, the tallest flagpole in the world was in San Francisco. a. ...

algebra - If you are standing 85 ft from the base of a flagpole, and determine ...

College Algebra - A person who is 6 feet tall walks away from flagpole toward ...

math - A flagpole stands at a right angle to the horizontal at the bottom of a ...

math - A flagpole casts a 32-ft shadow. A boy who is 6 feet tall is standing ...

Math-Trig - 1. To avoid a steep descent, an airplane flying at 10 000 m starts ...

Precalculus - A woman standing on a hill sees a flagpole that she knows to be 60...