Posted by **Anonymous** on Friday, December 2, 2011 at 8:06am.

a rectangular garden is to be fenced along four sides and in the middle it is to be divided into 2 equal areas.if 300meters of fencing materials is available, find the maximum possible area that can be fenced.

- math -
**Reiny**, Friday, December 2, 2011 at 11:06am
make a sketch, so you will have 2 longs sides and 3 short sides parallel with the divider.

Let the long sides by y, and the short sides be x

3x + 2y = 300

y = (300 - 3x)/2 = 150 - 1.5x

Area = xy

= x(150-1.5x)

= 150x - 1.5x^2

= -1.5(x^2 - 100x + 2500 - 2500)

= -1.5(x-50)^2 + 3750

Max area = 3750 m^2

check: x = 50, y = 75

area = 3750, 3x+2y= 150+150 = 300

## Answer This Question

## Related Questions

- Math - A rectangular rice land is to be fenced along 4 sides and in the middle ...
- Mathematics - A rectangular garden is to be fenced along four sides and is to be...
- Math - A rectangular garden is to be fenced off and divided into 3 equal ...
- engineering mathematics 1 - your father wants to fence a rectangular area in ...
- precalculus - A rectangular garden next to a building is to be fenced with 120 ...
- algebra 1 - Charles wants to build a vegetable garden such that three sides of ...
- Math - A rectangular garden is to be fenced by a farmer. One side of the garden ...
- 5th grade math - holly's garden is divided into 5 equal sections. she will fence...
- math - holly's garden is divided into 5 equal sections. she will fence the ...
- Precalculus - A farmer has 1000 feet of fencing materials available to fence a ...

More Related Questions