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October 31, 2014

October 31, 2014

Posted by **Erin** on Friday, December 2, 2011 at 5:09am.

y=2(x-3)^2-1

- Algebra 2 -
**Steve**, Friday, December 2, 2011 at 5:48amI'd graph it by

a) recognizing that it is a parabola, opening up

b) noting the vertex is at (3,-1)

c) the y-intercept is (0,17)

d) so, by symmetry is (6,17)

That should enable you to sketch the graph

x-intercepts are where

x = 3 +/- 1/√2

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