Posted by **Stacy** on Friday, December 2, 2011 at 1:10am.

definite Integrals (using fundamental Theorem)

Evaluate

from -1 to 2(x^2 - 4x)dx

- Calculus -
**drwls**, Friday, December 2, 2011 at 1:38am
[x^3/3 - 2 x^2] @ 2

MINUS

[x^3/3 - 2 x^2] @ -1

= [8/3 - 8] - [-1/3 -2]

= -16/3 + 7/3 = -3

- Calculus -
**Stacy**, Friday, December 2, 2011 at 2:13am
Thank you so much. I had the integral part, but was off on the rest. :)

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