Posted by jimmy on Friday, December 2, 2011 at 12:24am.
Let the numbers in order be unknown:
x x x x x x x x x x x x
minimum,maximum make it
50 x x x x x x x x x x 57
with 12 numbers the median is the average of the middle 2; let's make it easy:
50 x x x x 54 54 x x x x 57
Mode is 56, so toss at least 3 of them in (we already have two 54's). What the heck, toss them all in on the right:
50 x x x x 54 54 56 56 56 56 57
Now just fill in 4 values between 50 and 54. Keeping integers,
50 51 52 52 53 54 54 56 56 56 56 57
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