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September 16, 2014

September 16, 2014

Posted by **jimmy** on Friday, December 2, 2011 at 12:24am.

- math -
**Steve**, Friday, December 2, 2011 at 5:33amLet the numbers in order be unknown:

x x x x x x x x x x x x

minimum,maximum make it

50 x x x x x x x x x x 57

with 12 numbers the median is the average of the middle 2; let's make it easy:

50 x x x x 54 54 x x x x 57

Mode is 56, so toss at least 3 of them in (we already have two 54's). What the heck, toss them all in on the right:

50 x x x x 54 54 56 56 56 56 57

Now just fill in 4 values between 50 and 54. Keeping integers,

50 51 52 52 53 54 54 56 56 56 56 57

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