Sunday

December 21, 2014

December 21, 2014

Posted by **Jacqueline** on Friday, December 2, 2011 at 12:22am.

- Physics Honors -
**Steve**, Friday, December 2, 2011 at 12:31pmthe equation of motion for an object thrown from (0,0) at an angle θ with velocity v is

y(x) = -g/(2v^2 cos^2 θ) x^2 + xtanθ

the range (where y=0 again) is

r = v^2 sin2θ/g

the maximum height reached is

h = v^2 sin^2 θ/2g

So, we have

θ = 60°

v = 25

r = 25^2 * sin 120°/9.8

= 625 * 0.866 / 9.8

= 55.2m

**Answer this Question**

**Related Questions**

Physics Honors - A punter in a football game kicks a ball from the goal line at ...

AP physics - A NFL punter kicks a ball and lands 52 m away and is in the air ...

Physics - Soccer player kicks a ball down field. The ball's initial velocity is ...

physics - a kicker kicks a football from the 5 yard line to the 45 yd line ( on ...

Physics - 3. It’s fourth down in the big football game, and the game is tied ...

physics - Cameron kicks a football with an initial vertical velocity of 18.5 m/s...

addition and subtraction of vectors - In a soccer match, the goal keeper stands ...

physics - A football punter accelerates a football from rest to a speed of 9 m/s...

physics - a football punter accelerates a football from rest to a speed of 7 m/s...

physics - A football punter accelerates a football from rest to a speed of 10 m/...