Posted by Mei on Thursday, December 1, 2011 at 10:32pm.
"A ship leaves port on a bearing of 34.0 degrees and travels 10.4 mi. The ship then turns due east and travels 4.6 mi. How far is the ship from port, and what is its bearing from port?"
I would like to know how the actual steps in finding the answer please!

Math  Steve, Friday, December 2, 2011 at 5:22am
just start drawing your lines, and figure out how far each leg of the trip takes the ship. Start at (0,0)
go 10.4 mi at N34°E puts you at
(10.4*sin34°,10.4*cos34°) = (5.82,8.62)
Now go E for 4.6, and that adds (4.6,0) to the displacement. Now you are at
(10.42,8.62)
The new bearing θ is given by
tanθ = 10.42/8.62 = 1.2088
θ = 50.4°
distance is sqrt(182.88) = 13.52
or, 13.52mi at N50.4°E

Math  Hanna, Monday, May 23, 2016 at 8:41pm
not an answer, but steve, how did you get sqrt of 182.88? just wondering.

Math  cyanne, Wednesday, December 7, 2016 at 2:24pm
square 10.42 and 8.62 and add to get 182.88
Answer This Question
Related Questions
 TRIG HONORS CH: 5.8  a ship leaves port with a bearing of S 42deg W after ...
 TRIGONOMETRY  a ship leaves port with a bearing of S 42deg W after traveling 7 ...
 trig  a ship leaves port with a bearing of S 42deg W after traveling 7 miles, ...
 trig  Q1: Prove cos^2t+4cost+4/cost+2=2sect+1/sect Q2: A ship leaves port with ...
 Trig  A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the...
 Trig  A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the...
 Trig  A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the...
 Trig  A ship leaves port with a bearing of S 40 W. After traveling 7 miles, the...
 math precalculus  I've attempted this problem a few times but I can't get the ...
 Math Trigonometry  A ship leaves port and sails at a bearing of 124degrees. ...
More Related Questions