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March 30, 2015

March 30, 2015

Posted by **Kirsten** on Thursday, December 1, 2011 at 8:44pm.

- Calculus -
**Reiny**, Thursday, December 1, 2011 at 10:05pmLet the width of each of the smaller pens be x, and let the length of each of the smaller pens be y

So the total of all fences = 8x + 5y

8x + 5y = 1100

y = 220 - 8x/5

Area = 4xy

= 4x(220 - 8x/5)

= 880x - 32x^2/5

d(Area)/dx = 880 - 64x/5 = 0 for a max of area

64x/5 = 880

64x = 4400

x = 68.75

y = 220 - 8(68.5)/5 = 110

So each of the small pens should be 68.75 by 110

check my arithmetic

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