Thursday

December 18, 2014

December 18, 2014

Posted by **Kirsten** on Thursday, December 1, 2011 at 8:44pm.

- Calculus -
**Reiny**, Thursday, December 1, 2011 at 10:05pmLet the width of each of the smaller pens be x, and let the length of each of the smaller pens be y

So the total of all fences = 8x + 5y

8x + 5y = 1100

y = 220 - 8x/5

Area = 4xy

= 4x(220 - 8x/5)

= 880x - 32x^2/5

d(Area)/dx = 880 - 64x/5 = 0 for a max of area

64x/5 = 880

64x = 4400

x = 68.75

y = 220 - 8(68.5)/5 = 110

So each of the small pens should be 68.75 by 110

check my arithmetic

**Answer this Question**

**Related Questions**

Math PLEASE - It's about arithmetic sequence . . (the sum) SOLUTION PLEASE THANK...

Math PLEASE - It's about arithmetic sequence . . (the sum) SOLUTION PLEASE THANK...

Combinatorics - Calvin has 3 red juggling pins, 4 blue juggling pins, 5 white ...

Grade 9 Algebra Question 3 - TRIANGULAR NUMBERS By arranging bowling pins in ...

algebra (inequalities) - your club is in charge of making pins that students can...

math - How many 5-digit bank security Personal Identification Numbers (PIN) ...

7th grade math - Solve by applying the counting principal. When using a four ...

algebra - your club is in charge of making pins that students can buy to show ...

science - Miguel held a magnet 2cm above some steel safety pins.his magnet ...

Physics (mechanics) - There are two parts for this questions... "When a bowling ...