Posted by **Kirsten** on Thursday, December 1, 2011 at 8:44pm.

A farmer wishes to enclose a long rectangular pin that will then be divided into four separated, adjacent pins (all 4 pins are in a row) for different breeds of farm animals. He has 1100 feet of fencing available for use. What should the dimensions of the pin be so that he is able to maximize area? What is the maximum area?

- Calculus -
**Reiny**, Thursday, December 1, 2011 at 10:05pm
Let the width of each of the smaller pens be x, and let the length of each of the smaller pens be y

So the total of all fences = 8x + 5y

8x + 5y = 1100

y = 220 - 8x/5

Area = 4xy

= 4x(220 - 8x/5)

= 880x - 32x^2/5

d(Area)/dx = 880 - 64x/5 = 0 for a max of area

64x/5 = 880

64x = 4400

x = 68.75

y = 220 - 8(68.5)/5 = 110

So each of the small pens should be 68.75 by 110

check my arithmetic

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