Posted by **Kirsten** on Thursday, December 1, 2011 at 8:44pm.

A farmer wishes to enclose a long rectangular pin that will then be divided into four separated, adjacent pins (all 4 pins are in a row) for different breeds of farm animals. He has 1100 feet of fencing available for use. What should the dimensions of the pin be so that he is able to maximize area? What is the maximum area?

- Calculus -
**Reiny**, Thursday, December 1, 2011 at 10:05pm
Let the width of each of the smaller pens be x, and let the length of each of the smaller pens be y

So the total of all fences = 8x + 5y

8x + 5y = 1100

y = 220 - 8x/5

Area = 4xy

= 4x(220 - 8x/5)

= 880x - 32x^2/5

d(Area)/dx = 880 - 64x/5 = 0 for a max of area

64x/5 = 880

64x = 4400

x = 68.75

y = 220 - 8(68.5)/5 = 110

So each of the small pens should be 68.75 by 110

check my arithmetic

## Answer this Question

## Related Questions

- alegbra - A farmer wishes to fence in 3 different breeds of animals in a ...
- Math PLEASE - It's about arithmetic sequence . . (the sum) SOLUTION PLEASE THANK...
- Math PLEASE - It's about arithmetic sequence . . (the sum) SOLUTION PLEASE THANK...
- Combinatorics - Calvin has 3 red juggling pins, 4 blue juggling pins, 5 white ...
- quantitative techniques - a manufacturer of a cotter pins know that 5% of his ...
- Grade 9 Algebra Question 3 - TRIANGULAR NUMBERS By arranging bowling pins in ...
- algebra (inequalities) - your club is in charge of making pins that students can...
- math - How many 5-digit bank security Personal Identification Numbers (PIN) ...
- 7th grade math - Solve by applying the counting principal. When using a four ...
- Calculus - The Regional Farm Bureau (RFB) is preparing a brochure that offers ...

More Related Questions