magnesium nitrate decompses in water and releases ammonia gas. If 355ml of ammonia is produced at STP, whit is the mass of Magnesim nitrate that reacted. Equation is Mg3N2+6H2O=3Mg(OH)2+2NH3
You mean magnesium NITRIDE. Magnesium nitrate is Mg(NO3)2 and it does not produce NH3 when reacted with H2O.
Convert 355 mL NH3 to moles. moles = L/22.4 = ? moles NH3.
Convert moles NH3 to moles Mg3N2 using the coefficients in the balanced equation.
?moles NH3 x (1 mole Mg3N2/2 moles NH3) = ? moles Mg3N2.
Convert to grams. g = moles x molar mass.
To find the mass of magnesium nitrate that reacted, we need to use stoichiometry and the given volume of ammonia produced.
First, let's balance the equation:
Mg₃N₂ + 6H₂O → 3Mg(OH)₂ + 2NH₃
According to the balanced equation, 2 moles of ammonia are produced for every 1 mole of magnesium nitrate reacted.
To calculate the moles of ammonia produced, we need to convert the given volume of ammonia (355 mL) to moles at STP (Standard Temperature and Pressure). At STP, 1 mole of any gas occupies 22.4 liters.
Using the values:
Volume of ammonia = 355 mL
STP volume of 1 mole of gas = 22.4 L
Converting the volume of ammonia to liters:
355 mL = 355/1000 L = 0.355 L
Now, we can calculate the moles of ammonia produced:
Moles of ammonia = Volume of ammonia (in liters) / STP volume of 1 mole of gas
Moles of ammonia = 0.355 L / 22.4 L/mol = 0.0158 mol
According to the balanced equation, for every 2 moles of ammonia produced, 1 mole of magnesium nitrate reacts.
So, half the moles of ammonia produced will be equal to the moles of magnesium nitrate reacted.
Moles of magnesium nitrate reacted = 0.0158 mol / 2 = 0.0079 mol
Now, we need to find the molar mass of magnesium nitrate (Mg(NO₃)₂).
Molar mass of magnesium (Mg) = 24.31 g/mol
Molar mass of nitrogen (N) = 14.01 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Molar mass of magnesium nitrate (Mg(NO₃)₂) = (24.31 g/mol) + 2 * [(14.01 g/mol) + 3 * (16.00 g/mol)]
Molar mass of magnesium nitrate (Mg(NO₃)₂) = 148.33 g/mol
Finally, we can calculate the mass of magnesium nitrate reacted:
Mass = Moles * Molar mass
Mass = 0.0079 mol * 148.33 g/mol = 1.17 g
Therefore, the mass of magnesium nitrate that reacted is approximately 1.17 grams.