Posted by **LadyJ** on Thursday, December 1, 2011 at 2:19pm.

The vector position of a 3.00 g particle moving in the xy plane varies in time according to the following equation.

r1 = <(3i+3j)t + 2jt^2>

At the same time, the vector position of a 5.85 g particle varies according to the following equation.

r2 = <3i - 2it^2 - 6jt>

For each equation, t is in s and r is in cm. Solve the following when t = 2.10

(e) Find the net force exerted on the two-particle system.

____i ìN

____j ìN

## Answer This Question

## Related Questions

- physics - The vector position of a 3.80 g particle moving in the xy plane varies...
- Physics - The vector position of a 3.80 g particle moving in the xy plane varies...
- PHysics - The vector position of a 3.65 g particle moving in the xy plane varies...
- Physics - The vector position of a 3.45 g particle moving in the xy plane ...
- Physics - The vector position of a 3.45 g particle moving in the xy plane ...
- Physics - The vector position of a 3.45 g particle moving in the xy plane ...
- Physics - The vector position of a 3.45 g particle moving in the xy plane ...
- Physics - The vector position of a 3.40 g particle moving in the xy plane ...
- physics - The vector position of a 3.75 g particle moving in the xy plane ...
- physics - The acceleration of a particle moving only on a horizontal plane is ...

More Related Questions