Posted by **Macy** on Thursday, December 1, 2011 at 11:52am.

Let R be the region bounded by the x-axis, x = 5 and the curve

y = x. This region is rotated around the x-axis. Find the volume of the resulting

solid. (Note: R is a triangular region. The resulting solid has a simple shape.

You may ask me if you are highly unsure about what the solid "looks like.")

- Calculus -
**Steve**, Thursday, December 1, 2011 at 12:46pm
geometrically, the solid is a cone of height=5, radius=5

v = 125/3 pi

Analytically,

v = Integral(pi * y^2 dx)[0,5]

= Integral(pi * x^2 dx)[0,5]

= pi/3 x^3 [0,5]

= 125/3 pi

## Answer this Question

## Related Questions

- Calculus - This problem set is ridiculously hard. I know how to find the volume ...
- Calculus - 1. Find the area of the region bounded by the curves and lines y=e^x ...
- Calculus - We're learning disks, shells, and cylinders in school but we have a ...
- Calculus - We're learning disks, shells, and cylinders in school but we have a ...
- Calculus Help!! - Region R is bounded by the functions f(x) = 2(x-4) + pi, g(x...
- CALCULUS - The region R is bounded by the x-axis, y-axis, x = 3 and y = 1/(sqrt(...
- CALCULUS HELP PLZ - The region R is bounded by the x-axis, y-axis, x = 3 and y...
- Calculus - Let R be the square region bounded by y = 2, x = 2, and the x and y-...
- calculus - The region bounded by the curve y=1÷(1+2x) , the line X=2 , the x-...
- math - Let S be a region bounded by the curve y=x+cosx and the line y=x as shown...

More Related Questions