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April 25, 2015

April 25, 2015

Posted by **Jane** on Thursday, December 1, 2011 at 10:17am.

f(x,y)=1/SQRTx^2+y^2

- Calculus -
**Steve**, Thursday, December 1, 2011 at 10:55amtreat y as a constant:

f(x,y) = (x^2 + y^2)^.5

dy/dx = .5 (x^2 + y^2)^-.5 * (2x)

= x/sqrt(x^2 + y^2)