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December 20, 2014

December 20, 2014

Posted by **W** on Wednesday, November 30, 2011 at 10:28pm.

- Calculus -
**Reiny**, Wednesday, November 30, 2011 at 10:35pmx^2 + 2lny = y

2x + 2/y (dy/dx) = dy/dx

times y

2xy + 2 dy/dx = y dy/dx

2xy = y dy/dx - 2 dy/dx

2xy = dy/dx (y - 2)

dy/dx = 2xy/(y-2)

- Calculus -
**W**, Wednesday, November 30, 2011 at 10:51pmThank you! Now I understand that I should've multiplied by y instead of moving the whole "2/y (dy/dx)" to the other side of the equation and then factor the dy/dx out. I can't believe how such a simple manuever can make the problem so much easier to solve. Thanks again!

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