Posted by W on Wednesday, November 30, 2011 at 10:28pm.
x^2 + 2lny = y
2x + 2/y (dy/dx) = dy/dx
times y
2xy + 2 dy/dx = y dy/dx
2xy = y dy/dx - 2 dy/dx
2xy = dy/dx (y - 2)
dy/dx = 2xy/(y-2)
Thank you! Now I understand that I should've multiplied by y instead of moving the whole "2/y (dy/dx)" to the other side of the equation and then factor the dy/dx out. I can't believe how such a simple manuever can make the problem so much easier to solve. Thanks again!
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