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geometry

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in quadrilateral ABCD AC is a diagonol, m<ACD=2x+4 and m<ACB=5x-11 what proves ABCD a rhombus

  • geometry - ,

    It's a rhombus if the diagonal bisects the angles. So, if

    2x+4 = 5x-11

    the ABCD is a rhombus

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