Posted by **marko** on Wednesday, November 30, 2011 at 9:16pm.

i need to write the missing digit to make each number divisible by 3

1,843,#89

i got the missing number as : 3

s/b 1,843,389 is that right?

#2 i need to write the missing digit to make each number divisible by 8

2,4#2 i cant figure that out

i got : 2,422? is that right?

#3 i need to write the missing digit to make each number divisible by 8

1,325,#84

i got: 4

so should be: 1, 1,325,484 is that right?

- math divisibility -
**Reiny**, Wednesday, November 30, 2011 at 9:30pm
1. A number is divisible by 3 if the sum of its digits is divisible by 3

so far we have a sum of 33, which is divisible by 3

so the missing # could be 0, 3, 6, or 9

2. The fist 2 digits divide by 8, so #2 must divide by 8

only possible case is 32 or 72

3. Any number is divisible by 8 if its last 3 digits evenly divide by 8

184 does, so does 384, 584, 784, and 984

so 1325184, 1325384, etc

- math divisibility -
**people**, Tuesday, October 16, 2012 at 5:57pm
Didn't get a answer

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