1. A number is divisible by 3 if the sum of its digits is divisible by 3
so far we have a sum of 33, which is divisible by 3
so the missing # could be 0, 3, 6, or 9
2. The fist 2 digits divide by 8, so #2 must divide by 8
only possible case is 32 or 72
3. Any number is divisible by 8 if its last 3 digits evenly divide by 8
184 does, so does 384, 584, 784, and 984
so 1325184, 1325384, etc
Didn't get a answer
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