Posted by **Anne** on Wednesday, November 30, 2011 at 8:29pm.

A vertical spring with a spring constant of 400 N/m is mounted on the floor. From directly above the spring, which is unstrained, a 0.30 kg block is dropped from rest. It collides with and sticks to the spring, which is compressed by 2.7 cm in bringing the block to a momentary halt. Assuming air resistance is negligible, from what height (in cm) above the compressed spring was the block dropped?

- Physics -
**drwls**, Thursday, December 1, 2011 at 5:13am
Gravitational potential energy loss (at maximum compression) = Spring potential energy gained

(There is zero kinetic energy when the drop begins and when maximum compression is attained.)

M g H = (1/2) k *(0.027)^2

k is the spring constant, 400 N/m

H is the distance you want to know.

g = 9.8 m/s^2

M = 0.30 kg

Solve for H

## Answer This Question

## Related Questions

- Physics - A vertical spring with a spring constant of 400 N/m is mounted on the ...
- Physics - A vertical spring with a spring constant of 400 N/m is mounted on the ...
- Physics - A vertical spring with a spring constant of 410 N/m is mounted on the ...
- physics - 1.) A vertical spring with a spring constant of 450 N/m is mounted on ...
- physics - 1.) A vertical spring with a spring constant of 450 N/m is mounted on ...
- Physics - A vertical spring with a spring constant of 450 N/m is mounted on the ...
- Physics. Urgent - A vertical spring with a spring constant of 450 N/m is mounted...
- DrRuss/bobpursley/drwls please help!!! - Can you please clarify your response to...
- Physics - A 540 g block is released from rest at height h0 above a vertical ...
- Physics - A vertical spring with a spring constant of 450 N/m is mounted on the ...

More Related Questions