Posted by **Kristy** on Wednesday, November 30, 2011 at 8:15pm.

At noon, ship A is 180 km west of ship B. Ship A is sailing east at 40 km/h and ship B is sailing north at 30 km/h. How fast is the distance between the ships changing at 4:00 PM?

- Calculus -
**bobpursley**, Wednesday, November 30, 2011 at 8:27pm
draw the right triangle.

start the origin at B at noon.

a is the distance ship A moves in 4 hours.

a= -180+40*4=-20km

da/dt= + 40

b is the distance from the B starting point at noon.

b= 30*4=120

db/dt=30\

r=sqrt(a^2+b^2)

dr/dt= 1/2 *1/(a^2+b^2)* (2a da/dt+2b db/dt)

solve for dr/dt

- Calculus -
**Kristy**, Thursday, December 1, 2011 at 10:14pm
I tried plugging in the numbers for the variables, but I am not coming up with the right answer. I think the equation might be wrong.

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