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December 18, 2014

December 18, 2014

Posted by **Kristy** on Wednesday, November 30, 2011 at 8:15pm.

- Calculus -
**bobpursley**, Wednesday, November 30, 2011 at 8:27pmdraw the right triangle.

start the origin at B at noon.

a is the distance ship A moves in 4 hours.

a= -180+40*4=-20km

da/dt= + 40

b is the distance from the B starting point at noon.

b= 30*4=120

db/dt=30\

r=sqrt(a^2+b^2)

dr/dt= 1/2 *1/(a^2+b^2)* (2a da/dt+2b db/dt)

solve for dr/dt

- Calculus -
**Kristy**, Thursday, December 1, 2011 at 10:14pmI tried plugging in the numbers for the variables, but I am not coming up with the right answer. I think the equation might be wrong.

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