Posted by Kristy on Wednesday, November 30, 2011 at 8:15pm.
draw the right triangle.
start the origin at B at noon.
a is the distance ship A moves in 4 hours.
a= -180+40*4=-20km
da/dt= + 40
b is the distance from the B starting point at noon.
b= 30*4=120
db/dt=30\
r=sqrt(a^2+b^2)
dr/dt= 1/2 *1/(a^2+b^2)* (2a da/dt+2b db/dt)
solve for dr/dt
I tried plugging in the numbers for the variables, but I am not coming up with the right answer. I think the equation might be wrong.
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