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March 30, 2017

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CONSIDER THE FOLLLOWING UNBALANCED REDOX EQUATION:
IO3^-(AQ) + Al(S)-->I2(S) + A;^3+(AQ)

A. WHAT IS THE OXDATION NUMBER OF IODINE IN THE IODATE ION? I GOT IO3^6(AQ)?

B. WHICH SPECIES IS THE REDUCING AGENT I GOT AL^3+(AQ)

C. USING THE OXIDATION AND REDUCTION HALF REACTIONS WRITE THE BALANCED REDOX EQUATION

  • Chemistry - ,

    I is +5 in IO3^-
    B is correct.
    What's the problem with C?
    Al^3+ + 3e ==> Al is one half cell
    The other one is
    2IO3^- + 10 e + 12H^+ = I2 +6H2O
    I assume an acid solution.

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